Ea Design a concrete mix for the volume method ollowing cond
Solution
SOLUTION :
Target Mean Strength = 30 + 3 = 33 Mpa
ABSOLUTE VOLUME (V)
Absolute Volume = weight of material / (specific gravity of material x unit weight of water)
Take unit weight of water = 998 kg/m3
Absolute Volume for Coarse Aggregate = (1602 ) / (2.68 * 998) = 0.599 m3
Take Natural sand unit weight = 1520 kg/m3
Absolute Volume for Fine Aggregate = (1520 ) / (2.63 * 998) = 0.579 m3
Absolute Volume for Cement = (1440 ) / (3.15 * 998) = 0.458 m3
So total Volume = 0.599 + 0.579+0.458 = 1.636 m3
Water is assumed to be 5% = 1.636 * 1.05 = 1.72 m3
Air is only entariner is allowed so assumed as 4% = 1.72 * 1.04 = 1.79m3
So the Volume of Air is = 1.79 - 1.72 = 0.07 m3
To find
BULK SPECIFIC GRAVITY SATURATED SURFACE DRY (Gs(ssd)) for CA
Gs(ssd) = (1 + Absorption) x Gs(dry)
= (1+0.005) * 2.68 =2.693
BULK SPECIFIC GRAVITY SATURATED SURFACE DRY (Gs(ssd)) for FA
Gs(ssd) = (1 + Absorption) x Gs(dry)
= (1+0.013) * 2.63 =2.66
WATER-CEMENT RATIO (w/c) = 0.5
Weight of Fine Aggreagate = 0.579 * 2.66 * 998 = 1537.06 kg
Weight of Course Aggreagate = 0.599 * 2.693 * 998 = 1609.88 kg
Weight of Cement = (0.458 * 3.15 * 998) / 4.2 = 342.8 kg
Observations should be conduct with the above mix proportions
we should get with more than 30 samples 33Mpa. If not achived we should increase the ceemnt and water by 2.5% and again test with obserations.

