A student of business is interested in estimating a 95 confi

A student of business is interested in estimating a 95% confidence interval for the proportion of students who bring laptops to campus. He wishes a precise estimate and is willing to draw a large sample that will keep the sample proportion within six percentage points of the population proportion. What is the minimum sample size required by this student, given that no prior estimate of the population proportion is available? (Round intermediate calculations to 4 decimal places and \"z\" value to 2 decimal places. Round up your answer to the nearest whole number.)

Solution

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.05 is = 1.96
Samle Proportion = 0.5
ME = 0.06
n = ( 1.96 / 0.06 )^2 * 0.5*0.5
= 266.778 ~ 267