Please help with this one A psychology professor asked her s
Please help with this one.
A psychology professor asked her sophomore students \"Does either of your parents allow you to drink alcohol around him or her?\" and when drinking (not necessarily around your parent) \"How many drinks do you typically have per session?\" (For these purposes, a drink is defined as a 12 oz. beer, a 4oz. glass of wine, or a one oz. shot of liquor.)
The next tables contains the responses from female students who are not abstainers.
Drinks per session for students whose parent allows them to drink
Drinks per session for students whose parents do not allow them to drink
If you treat these two samples as SRSs, do they provide significant evidence at the 1% level that the behavior of the parents affects how many drinks the students have on average?
Formulate H0 and Ha .
a. Give the test statistic:
b. Give the P -value:
c. Your decision for the hypothesis test:
A. Reject H0 .
B. Do Not Reject Ha .
C. Reject Ha .
D. Do Not Reject H0 .
| 2.5 | 1 | 2.5 | 3 | 1 | 3 | 3 | 3 | 2.5 | 2.5 | 3.5 | 5 | 2 |
| 7 | 7 | 6.5 | 4 | 8 | 6 | 6 | 3 | 6 | 3 | 4 | 7 | 5 |
| 3.5 | 2 | 1 | 5 | 3 | 3 | 6 | 4 | 2 | 7 | 5 | 8 | 1 |
| 6 | 5 | 2.5 | 3 | 4.5 | 9 | 5 | 4 | 4 | 3 | 4 | 6 | 4 |
| 5 | 1 | 5 | 3 | 10 | 7 | 4 | 4 | 4 | 4 | 2 | 2.5 | 2.5 |
Solution
Ho:there is no significant difference between two sample averages among the behaviour of the parents which allows them and does allow them to drink. H1:Ho:there is no significant difference between two sample averages among the behaviour of the parents which allows them and does allow them to drink. Then we use test statistic as Z=|x1bar-x2bar|/([(21/n1)+(22/n2)])=|4.1769-4.5517|/[[(4.0284/65)+(5.6784/29)]]=0.3747/0.5077=0.7382. And the table value of Z at 1% level of significance is 2.58. So Zcal<Ztab, we accept Ho, i.e., do not reject Ho. Therefore, there is no significant difference between two sample averages among the behaviour of the parents which allows them and does allow them to drink.
