Problem I Find the probabilities that a random variable hav
Solution
a)
z1 = lower z score =    0.87      
 z2 = upper z score =     1.28      
           
 Using table/technology, the left tailed areas between these z scores is          
           
 P(z < z1) =    0.807849798      
 P(z < z2) =    0.899727432      
           
 Thus, the area between them, by subtracting these areas, is          
           
 P(z1 < z < z2) =    0.091877634   [ANSWER]
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b)
z1 = lower z score =    -0.34      
 z2 = upper z score =     0.62      
           
 Using table/technology, the left tailed areas between these z scores is          
           
 P(z < z1) =    0.366928264      
 P(z < z2) =    0.732371107      
           
 Thus, the area between them, by subtracting these areas, is          
           
 P(z1 < z < z2) =    0.365442843   [ANSWER]  
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c)
Using a table/technology, the right tailed area of this is          
           
 P(z >   0.85   ) =    0.197662543 [ANSWER]
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d)
Using a table/technology, the right tailed area of this is          
           
 P(z >   -0.65   ) =    0.742153889 [ANSWER]
   

