Problem I Find the probabilities that a random variable hav
Solution
a)
z1 = lower z score = 0.87
z2 = upper z score = 1.28
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.807849798
P(z < z2) = 0.899727432
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.091877634 [ANSWER]
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b)
z1 = lower z score = -0.34
z2 = upper z score = 0.62
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.366928264
P(z < z2) = 0.732371107
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.365442843 [ANSWER]
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c)
Using a table/technology, the right tailed area of this is
P(z > 0.85 ) = 0.197662543 [ANSWER]
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d)
Using a table/technology, the right tailed area of this is
P(z > -0.65 ) = 0.742153889 [ANSWER]
