Solve the vectors A989 theta A161 degrees in quadrant I B581

Solve the vectors. A=98.9 theta A=16.1 degrees in quadrant I, B=58.1 theta B=28.7 degrees in quadrant II.

A=98.9 theta A=16.1 degrees in quadrant I, B=58.1 theta B=28.7 degrees in quadrant II.

a = 98.9

A = 16.1

b = 58.1

B = 180 - 28.7 deg = 151.3

Now,

Rx = a cosA + b cosB

Rx = 98.9 cos16.1 + 58.1 cos 151.3

Rx = 44.05

Ry = a sinA + b sinB

Ry = 98.9 sin16.1 + 58.1 sin 151.3

Ry = 55.32

theta = (55.32/44.05) = 51.47 deg.

R = sqrt(Rx^2 + Ry^2) = 70.71