Appendix B6 is a table of random numbers Hence each digit fr

Appendix B.6 is a table of random numbers. Hence, each digit from 0 to 9 has the same likelihood of occurrence. A table of random numbers is given below. Assume that these are 5 random samples of five values each.

Solution

Mean of 1st sample = (0+0+2+7+7)/5 = 3.2

Mean of 2st sample = (7+1+9+2+3)/5 = 4.4

Mean of 3rd sample = (1+4+6+1+5)/5 = 3.4

Mean of 4th sample = (0+0+8+4+3)/5 = 3

Mean of 5th sample = (7+2+4+8+0)/5 = 4.2

Mean of the sample mean = (3.2 + 4.4 + 3.4 + 3+ 4.2)/5=3.64

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