Homework SourseThe following is a binomial distribution with n3 and Pi 032
The following is a binomial distribution with n=3 and Pi= 0.32.
X P(x)
0 0.314
1 0.444
2 0.209
3 0.033
The variance of the distribution is
A) 0.960
B) 0.653
C) 0.240
D) 0.384
The following is a binomial distribution with n=3 and Pi= 0.32.
X P(x)
0 0.314
1 0.444
2 0.209
3 0.033
The variance of the distribution is
A) 0.960
B) 0.653
C) 0.240
D) 0.384
X P(x)
0 0.314
1 0.444
2 0.209
3 0.033
The variance of the distribution is
A) 0.960
B) 0.653
C) 0.240
D) 0.384
Solution
the variance of X is E(X^2 ) E(X) ^2 = E X(X 1) + E(X) E(X) ^2 = n(n 1)p^ 2 + np (np)
= np(1 p)
n = 3, p = 0.32, 1-p =0.68
therefore variance = 0.653
