Solve the following trigonometric equation Solve the followi

Solve the following trigonometric equation

Solve the following trigonometric equation 6sin^2 + 5sinx = 6, 0 lessthenorequalto x lessthenorequalto 90degree

6sin^2x +5sinx =6

6sin^2x +5sinx -6 =0

0<=x<=90

solve the quadratic equation: x = (-5 +/- sqrt(5^2 +4*6*6)/12

=(-5+/- 13)/12

=-18/12 , - 8/12

ignore sinx = -18/12 s sincnnot be greater or less than 1

So, we have sinx = -2/3

x = sin^-1(-2/3) = -41.82 deg

value of x is not in the given interval

So, no solution