Here are five hypothetical reactions numbered 15 1 A B G 5
Here are five hypothetical reactions (numbered 1-5).
1. A B G°\' = -5 kJ/mol
2. B C + D G°\' = +8 kJ/mol
3. B E G°\' = -10 kJ/mol
4. E F G°\' = +5 kJ/mol
5. D F G°\' = +1 kJ/mol
From these five reactions it is possible to write TWO metabolic paths that could generate the metabolite F starting with metabolite A. Which of these two pathways will proceed spontaneously based on the overall G°\' value?
Question options:
1, 5
1, 3, 4
1, 3, 5
1, 2, 5
The answer is NOT C.
| 1, 5 | |
| 1, 3, 4 | |
| 1, 3, 5 | |
| 1, 2, 5 The answer is NOT C. |
Solution
The option 1 and 2 are correct.
For option 1: the production of F can be achieved if it is produced by substrates E or D. It is because these two only are making product F. in the option D---F is mentioned so the process require 1 kJ/mol energy which can be gain from A---B ( because it generates 5 kJ/mol energy; which is sufficient). It is possible because the final product F is required whether it come from any way. It is not necessary to have a reaction which makes B---D. Also cells always tend to spend less energy.
For option 2: it is achieved because overall reaction energy is -10KJ/mol. It is spontaneous.
The other options:
3: it is an unnecessary reaction because not considering sequential products. The B---E is unnecessary when there is no conversion of E—F. the question require product F starting with metabolite A. The fourth option is not favorable because of overall +4KJ energy.
