Calculate the forces in cables when lifting a M939 21470 pou

Calculate the forces in cables when lifting a M939 21,470 pound military vehicle that has been driven onto a platform that can be lifted by a 25degree cable that splits into 4 individual cables that attach at each comer of the platform. The platform is assumed to be the L*W of the vehicle, plus 20% of the H in all directions. The single supporting cable makes its split into 4 cables at 200% of H above the platform.

Solution

Weight = 9740 * 9.8 = 95452 N

Length of the platform   = 307.4 + 0.2 * 115   = 330.4 in

Width of the platform   = 97.5 + 0.2 * 115   = 120.5 in

Height where cable splits   = 115 * 2   = 230 in

Angle formed by a single cable with the platform   = tan^-1(230 / sqrt(165.2^2 + 60.25^2) )

                                                                         = 52.6 degrees

4 * T * sin(52.6)   = weight   = 95452

Tension = 30038.2 N