Hisako ran a crosscountry race in which the course was divid
Hisako ran a cross-country race in which the course was divided into 3 equal legs. Hisako ran the first leg at 12 km/h and the last two legs at 16 km/h. The whole race took her 50 min. How long was each leg? How long was the entire course?
 
 I know the solution is something like this:
 12t + 16t + 16t = d
Solution
seeing as the distances are all the same you have three legs whose additive times equal 50 min.
 d=rt or:
 t=d/r
 d/12+d/16+d/16=5/6 find a common denominator for the left hand side of this equation.
 48 looks like a good choice.
 (4d+3d+3d)/48=5/6
 10d/48=5/6 cross multiply
 60d=5*48
 60d=240
 d=240/60
 d=4 k for the distance of each leg.
 proof
 4/12+4/16+4/16=5/6
 (4*4+3*4+3*4)/48=5/6
 (16+12+12)/48=5/6
 40/48=5/6
 5/6=5/6

