3Find the x and yintercepts of the relation 2x 3y 12 A 400

3.Find the x- and y-intercepts of the relation: 2x – 3y = -12

(A) (4,0)&(0,-6)     (B) (-6,0)&(0,4)     (C) (-4,0)&(0,6)   (D) (-6,0)&(0,-4)

Solution

2x – 3y = -12

for x intercept y =0

2x -3(0)=-12

2x=-12

x=-6

x intercept =(-6,0)

for y intercept x=0

2(0) -3y =-12

-3y=-12

y=4

y intercept =(0,4)

optiion B