x y 3 2x 3y 4Solutionx y 3 1 and 2x 3y 4 2 On multip

x + y = 3 2x +3y = 4

Solution

x + y = 3 .... ...(1) and

2x + 3y = 4 ....(2)

On multiplying both the sides of 1st equation by 2 ( to eliminate x), we get 2x + 2y = 6 ...(3)

Now, subtracting the 3rd equation from the 2nd equation gives us 2x + 3y - 2x -2y = 4 - 6 or, y = - 2.

On substituting this value of y in the 1st equation, we get x + ( -2) = 3 or, x - 2 = 3 or, x = 3 + 2 = 5

Thus the answer is x = 5 and y = -2. We can verify this answer by substituting these values of x and y in the given equations.

 x + y = 3 2x +3y = 4Solutionx + y = 3 .... ...(1) and 2x + 3y = 4 ....(2) On multiplying both the sides of 1st equation by 2 ( to eliminate x), we get 2x + 2y

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