Because the cylinder can roll on the conveyor belt the cente

Because the cylinder can roll on the conveyor belt, the center of the cylinder (point O) can have speed that is more than that of the conveyor belt.

At the instant shown the angular velocity of the package is ? = 15 rad/s and the radius is R = 0.5 ft.

If the horizontal speed of the conveyor belt is vconveyor = 2ft/s, what is the velocity vector of point A along the edge of the cylinder? Assuming the cylinder rolls without slipping on the conveyor belt.

Solution

The cylinder rolls with ang vel 15, radius 0.5

Point A has local velocity of 7.5j wrt the cylinder

the velocity of the cyinder is that of the centre of mass which has velociy wrt the belt of 7.5i

in addition the belt is moving at 2i

total abs vel of point A 9.5i +7.5j