A right triangle is given with the legs a and b, and the hypotenuse c. (The angles across from the corresponding sides are A, B and C). If a = 30 and c=40. Find: (4pt) a. leg b. b. Angle A Convert/7 to degree measure. Round your answer to the nearest degree. Solve: (Give your answer in radian measure!)(8pt) a. Sin x = .2 b. Cos x-2/3 c. Tan x=5 d. Cot x- - 2 e. Sec x = 4 f. Csc x = 1 g, 3sin x = 2 h. Sin x-2 sin x-0 3. 4. 5. 
3)C=900
 by law of sines a/sinA=c/sinC
 30/sinA=40/sin900
 sinA=30/40
 A=48.590
 B=180-90-48.59=41.410
 by law of sines b/sinB=c/sinC
 b/sin41.410=40/sin900
 b=40sin41.410
 b =26.46
 4)/7
 =(/7)*(180o/)
 =180o/7
 =25.70
 =260