Events A and B are mutually exclusive Suppose event A occurs

Events A and B are mutually exclusive. Suppose event A occurs with probability0.13 and event B occurs with probability 0.16. a Compute the probability that B occurs or A does not occur (or both) b. Compute the probability that neither the event A nor the event B occurs.

Solution

Let\'s list all the probabilities:

P(A) = 0.13

P(not A) =0.87

P(B) = 0.16

P(not B) = 0.84

a)So P(A and not B) = P(A)P(not B) = 0.13 x 0.84=0.1052

b) P(not A and not B) = P(not A)P(not B) = 0.87x 0.84= 0.7308