In the figure R 50 ohm L 80 H the ideal battery has E 190

In the figure. R = 5.0 ohm, L = 8.0 H, the ideal battery has E = 19.0 V, and the fuse in the upper branch is an ideal 1.0 A fuse. It has zero resistance as long as the current through It remains less than 1.0 A. If the current reaches 1.0 A, the fuse \"blows\" and thereafter has infinite resistance. Switch S is dosed at time t = 0. When does the fuse

Solution

As the resistor is in parallel with the fuse = 0 ohms

V = L * di/dt

Time = Current * Inductance / Voltage

t = I L / V

= (1.0 A * 8) / 19

t = 0.421 s