Identify the amplitude and period from the graph Solution1 m

Identify the amplitude and period from the graph:

Solution

1)
max = 4 , min = -4
So, amplitude = (max - min)/2
A = (4 - (-4))/2
A = 8/2
A = 4

PEriod :
Notice it hits the max at x = 0 and then at x = 4pi
So, period = 4pi

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2)
max = 3, min = -3
So, amplitude = (max - min)/2
A = (3 - (-3))/2
A = 6/2
A = 3

Period :
Notice it hits 0 at pi/2 and then for the third time at 3pi/2
So, period = 3pi/2 - pi/2
Period = pi

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3) max = 2 and min = -2
So, amplitude, A = (max - min)/2
A = (2 - (-2))/2
A = 4/2
A = 2

Period :
Starts at x =0 and then one period ends at x = 2
So, period =2

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4)
max = 2 and min = -2
A = (max - min)/2
A = (2 - (-2))/2
A = 4/2
A = 2

Period :
Hits the minimum at x = 0 then minimum again at x = 2pi
So, period = 2pi

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5)
max = 5 and min = -5
A = (max - min)/2
A = (5 - (-5))/2
A = 10/2
A = 5

Period :
Hits 0 at x = -3/4, then hits the third 0 at x = 9/4
So, period = 9/4 - (-3/4)
Period = 12/4
Period = 3