a2 c1 B10 degrees 2 Find the area of the trianglegiven the f

a=2, c=1, B=10 degrees

2.) Find the area of the triangle,given the following.

a=5, b=8, c=9

3.) write the expression in the standard form a+bi.

4.) Find the unit vector in the same direction as the vector v= -5i+12j.

Write the expression in the standard form a bi. 5TT 2 cos i sin 16 16

1)a=2, c=1, B=10^o

by law of cosines

b²=a²+c²-2accosB

b²=2²+1²-2*2*1*cos10^o

b²=1.06077

b=1.03

by law of sines a_/sinA=b_/sinB=c_/sinC

2_/sinA=1.03_/sin10^o=1_/sinC

sinA=(2_/1.03)sin10^o

A=160.3^o

sinC=(1_/1.03)sin10^o

C=9.7^o,

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2)a=5, b=8, c=9

s=(a+b+c)_/2=(5+8+9)_/2 =11

area of triangle=[s(s-a)(s-b)(s-c)]

area of triangle=[11(11-5)(11-8)(11-9)]

area of triangle=396

area of triangle=19.9 square units