The solutions in the two arms of this Utube are separated by

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with an aqueous solution of 2 mols of sucrose and 1 mol of glucose. Side B is half-tilled with an aqueous solution of 1 mol of sucrose and 2 mols of glucose. Initially, the liquid levels on both sides are equal. A. Initially (before any diffusion takes place), what is the tonicity of side A with respect to (compared to) side B? Isotonic Hypertonic Hypotonic After diffusion and equilibrium: _____ How many mols of sucrose are on side A?_____ side B? _____ How many mols of glucose are on side A?_____ side B? After diffusion what would you observe in the water level in side A? an increase in the water level. no change in the water level a decrease in the water level

Solution

1. Firstly we should know that sucrose is disaccharide and glucose is monosaccharide, one sucrose molecule is made up of one glucose and one fructose. Fructose also a monosaccharide.

A side contain 2 moles of sucrose and one mole of glucose, so A side contain total 5 moles of monosaccharide. Likewise side B contain 1 mole of sucrose and 2 moles of glucose, so B side contain total 4 moles of monosaccharide. Side A contain hypertonic solution as compared to side B.

B. 2 mole sucrose on side A and 1 mole on side B

0.5 mole glucose on side A and 2.5 mole glucose on side B

C. Ans: an increase in the water level

We know that in diffusion solvent molecule moves from lower concentration gradient to higher concentration gradient. After diffusion water level of side A will increase.