| 3. | A sample of 25 outcomes is taken from a population that is Normal(50, 3). The mean of this particular sample is found to be 48.5. Find the probability that one particular observation in this sample is less than 48.5. |
| | a.) | 0.0062 | | b.) | 0.3085 | | c.) | 0.6915 | |
| 3. | A sample of 25 outcomes is taken from a population that is Normal(50, 3). The mean of this particular sample is found to be 48.5. Find the probability that one particular observation in this sample is less than 48.5. |
| | a.) | 0.0062 | | b.) | 0.3085 | | c.) | 0.6915 | |
Mean ( u ) =48.5
Standard Deviation ( sd )=3/ Sqrt ( 25 ) = 0.6
Number ( n ) = 25
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)
P(X < 48.5) = (48.5-50)/3/ Sqrt ( 25 )
= -1.5/0.6= -2.5
= P ( Z <-2.5) From Standard NOrmal Table
= 0.0062
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