solve dydx 2xy y01Solutiondydx 2xy dyy 2xdx integertaiung

Solution

dy/dx = 2xy,

dy/y = 2xdx

integertaiungb on both sides,

lny = x^2 +c

plugging thye initial condition,

ln1 = 0 +c

c = 0

lny = x^2

y = e^{x^2}