M4i9 12 You D Pathways lMathAS Assess eHome Cheggcom https

M4i9 #12

You D Pathways lMathAS Assess ×(eHome | Chegg.com -> https://imathas.rationalreasoning.net/assessment/showtest.php?action-skip&to;=11&reattempt-11; For quick access, place your bookmarks here on the bookmarks bar. Import bookmarks now... a @ Home > Murdock Precalc 013> Assessment Jeremee Hemphill M4 I9 Homework Due in 7 hours, 12 minutes. Due Wed 04/27/2016 11:59 pm Show Intro/Instructions Questions A 32 mg of a vaccine is given to a patient to prevent measles. The vaccine leaves the body at a rate of 5.9% per hour. a. Represent the number of hours that have elapsed h days after the vaccine was initially injected into the body 24h Preview Q2 [4/4] Q4 [3/3] b. The number of milligrams of vaccine in the body after h days is how many times as large as the number of milligrams of vaccine initially injected into the body? Preview c. Define a function k that determines the number of milligrams of vaccine remaining in the body in terms of the number of days, n, since the vaccine was administered Preview d. After how many days were there 20 milligrams of vaccine in the body? Q 10 [1/1] Q 11 [3/3] C Q 12 (1/5) C Q13 (2/3) C Q 14 (0/3) C Q 15 (0/3) C Q 16 (0/3) Q17 (0/6) C Q 18 (0/4) Q19 [1/1] review e. After how many days were there 9 milligrams of vaccine in the body? review License Points possible Unlimited attempts Score on last attempt: 1. Score in gradebook: 1 Post this question to forum Grade: 39/63 Submit Print Version 4:47 PM l.)-.111 4/27/2016

Solution

a) 24*h = 24h hours

b) Number of milligrams after h days can be given by

decay equation = 32(1-0.059)^24h = 32(0.941)^24h

Number of miiligrams after h days is 32(0.941)^24h /32 = (0.941)^24h times the initial amt,

c) n days = n*24 = 24n hrs

Amt of milligrmas remaining =32(0.941)^24n

d) Remaining = 20mg

20 = 32(0.941)^24n

0.625 = 0.941^24n

take log on both sided:

ln(0.625) = 24n*ln(0.941)

n = 0.322 day = 0.3 day

d) Remaining 9 mg

9 = 32(0.941)^24n

20.85 = 24n

n= 0.87 day