A company has three production plants each of which produces
     A company has three production plants, each of which produces three different models of a particular product. The daily capacities (in thousands of units) of the three plants are as follows.  The total demand for Model 1 is 300,000 units, for Model 2 is 172.000 units, and for Model 3 is 249.5(H) units. Moreover, the daily operating cost for Plant I is $55,000. for Plant 2 is $60,000. and for Plant 3 is $60,000. How many days should each plant be operated in order to fill the total demand, and keep the operating cost at a minimum? 
  
  Solution
Let plant 1 be operated for x days, 2 for y days and 3 for z days
Then Operating cost C= 55000x+60000y+60000z
Our objective is to minimise C
Constraints are: The demand
The constraints can be represented as
8x+6y+12z>=300000 - I
4x+6y+4z>=172000 - II
8x+3y+8z>=249500 - III
I - III gives 3y+4z >= 50500
2(II)-III gives 9y >= 94500
y>= 10500
Substitute in 3y+4z >=50500
4z >= 40000 : z >=10000
Substitute in I
8x+6y+12z>=300000
8x + 63000+120000>=300000
8x >= 117000
x>=14625
Thus x = 14625
y = 10500
z = 10000
will meet the full demand at the same time keep the cost at minimum as plants willbe utilized fully.
Min cost C = 55000(14625) +10500(60000)+10000(60000)
= 807375000+630000000+600000000
= 2034375000

