For the vector squareroot 22 1 Find the magnitude and direct

For the vector (squareroot 22, -1), Find the magnitude and direction angle (to the nearest tenth). Give the measure of the direction angle as an angle in [0 degree, 360 degree].

Solution

Vector (sqrt22,-1)

magnitude=sqrt(sqrt22² + (-1)²) = sqrt 23

direction,tan theta = y/x

tan theta=-1/sqrt22

theta = tan^-1(-1/sqrt22) = approx 168 degree