You have a stock solution that contains 79 mM calcium carbon

You have a stock solution that contains 79 mM calcium carbonate. You need to make 65 mL of a solution that contains 4 m calcium carbonate. How many Ml of the stock solution do you need to use?

Solution

Answer;

Stock = 79 mM

Required = 4 mM

Required Volume = 65 mL

C1V1= C2V2

(stock)   (required)

V1=C2V2/C1

V1 = (4 mM X 65 mL)/ 79 mM

= 3.29 mL

3.29 mL of stock + 61.7 mL of H2O gives 4mM CaCO3 solution