In a doubleslit interference experiment the wavelength is 6

In a double-slit interference experiment, the wavelength is = 602 nm, the slit separation is d = 0.160 mm, and the screen is D = 34.0 cm away from the slits. What is the linear distance between the 6th order maximum and the 4th order maximum on the screen?

x = _______mm

Solution

= 602 nm , d = 0.160 mm , D = 34.0 cm , m = 4,6

now Ym = mL/d   

dY = Y6-Y4

dY = 6L/d - 4L/d = 4L/d = (4*602*10^-9*34*10^-2)/(0.160*10^-3) = 0.00511 m OR 5.11 mm