Please complete the problems showing all calculations and eq

Please complete the problems showing all calculations and equations on which you base your answers. Use if applicable -9.8 m/s2 as the value for the acceleration due to gravity. Please be advised below questions is for Biomechanics class.

Assume that (a) the radius of gyration C\"k\") of the thigh with respect to an axis (through the segment\'s center ofmass) is 34% of the segment length, (b) the mass of the thigh is 10.4% of total body mass, (c) the length of the thigh is 22.8% of total body height, and (d) the center of mass of the thigh is 42% of the segment length from its proximal axis. (All the information you need is given here. No need to use tables) What is the moment of inertia of the thigh about a transverse axis through the hip joint center of rotation for each of the following two individuals? (Express your answers in metrie system (SI) units) (Express your answers in metric system (SI1) units) Subject A Subject B Weight Height 147 lbs. 5\'6\" 185 lbs. 6\'0\"

Solution

subject A :

weight = 147 lbs =     height = 5\'6\" = 66\'

mass of thigh = 147*10.4/100 = 15.28 lbs = 6.935 kg

length of thigh = 66*22.8/100 = 15.05 in = 0.38 m

radius of gyration k = 0.38*0.34 = 0.13 m

COM from proximal axis = 0.42*0.38 = 0.16 m

MI = Mk²   = 6.395 *0.13² = 0.19 kg-m² , momentof inerti of the thigh about its COM

we want MI about an axis through the hip joint,

we use the parllel axis theorm

I = I_com +Md²    d= 0.16 m

= 0.19 + 6.395*0.16²   = 0.354 kg-m²

subject B :

weight = 185 lbs =     height = 6\'0\" = 72\'

mass of thigh = 185*10.4/100 = 19.02 lbs = 8.63 kg

length of thigh = 72*22.8/100 = 16.42 in = 0.417 m

radius of gyration k = 0.38*0.417 = 0.158 m

COM from proximal axis = 0.42*0.417 = 0.175 m

MI = Mk²   = 8.63 *0.158² = 0.215 kg-m² , momentof inerti of the thigh about its COM

we want MI about an axis through the hip joint,

we use the parllel axis theorm

I = I_com +Md²    d= 0.175 m

= 0.215 + 8.63*0.175²   = 0.479 kg-m²