Please answer 10,12,13,14,15.
 Know what is meant by the term percent (%) solution. (Answer: % = g/100 ml) Be able to calculate it.  Sample problem - Given: the mass of hydrogen is 1.0, the mass of carbon is 12.0, the mass of oxygen is 16.0, and the chemical formula for glucose is C_6H_12O_6. What is the molarity of a 10% glucose solution? (Answer: 0.56 M)  Know solution, solvent, solute, and solubility.  Know the Lowry-Bronsted definition of acid and of base. Define: dissociation, strong vs. weak acid, strong vs. weak base, conjugate base, pH. What is the relationship between each of these and the concentration of hydrogen ions? Understand the pH scale, and, if given hydrogen ion concentration, be able to calculate pH.  Know biomolecules: carbohydrates, lipids, proteins, nucleic acids. Specifically, know primary functions of each, some properties of each, the building blocks of each, and some examples of each. (For example, to which category does glucose belong? What are the building blocks of proteins? To which group of molecules do steroids belong?)  Know adenosine triphosphate (ATP). How docs ATP provide energy to the cell? What is the relationship between ATP and ADP?  Know structure, location, and function of: nucleus, ribosomes, rough endoplasmic reticulum (ER), organelles, smooth ER, Golgi complex, vesicles, lysosomes, mitochondria, cytoskeleton, vaults, secretary vesicles, cytosol.
Percent solution tells the proportion of solute into a solution.
 Solute +Solvent = Solution
 For glucose C6H12O6 we have to calculate its molecular mass
 Molecular mass = A1 x b1 + A2x b2 + ...+An x bn   [where A is Atomic mass of element and b is number of atoms in that molecule.]
 Now molecular mass of glucose = 12x6 + 1x12 + 16x6 = 72+12+96 =180
  For 100% glucose solution, 100 g of glucose should dissolve in 100 ml of water.
 To calculate the required weight of glucose for 10% glucose solution we use the following formula:
 W1 x P2 = W2 x P1 where W is weight and P is percentage of solution
 100 x 10 = W2 x 100
 W2 = 10 g
  180 g glucose is always 1 mol.
 To calculate moles of 10 g glucose in the solution we use following formula:
 Grams of glucose/ molecular mass = 10 / 180 =1/18 moles
 In terms of molarity we use following formula:
 Number of moles/ liter of solution = (1/18) / (100ml / 1000ml)                     [to calculate 100 ml solution]
 = 0.056 / 0.1 = 0.56 M