Material for this Lab Experiment 6 Manual General Lab Docume

Material for this Lab Experiment 6 Manual General Lab Documents TOC and Introduction Appendix A: Error Analysis for the Physics Labs Appendix B: Introduction to Spreadsheets and EXCEL 2010 Problem Statement: Consider the following: If 10.0 mA of current flows through a 100.0 Ohm resistor, what is the voltage drop in V across the resistor? Numeric : A numeric value is expected and not an expression. Material for this Lab Experiment 6 Manual General Lab Documents TOC and Introduction Appendix A: Error Analysis for the Physics Labs Appendix B: Introduction to Spreadsheets and EXCEL 2010 Problem Statement: A sine wave has an RMS amplitude of 2.0 V. What is the peak-to-peak voltage in V of the wave? Numeric : A numeric value is expected and not an expression.

Solution

Problem 4: For a resistor with resistance R and current flowing through it as I, the net potential drop across it is given by V = RI

That is, for the given resistor and current, V = 10 x 10^-3 x 100 = 1 volt

Problem 5: For the RMS amplitude of v, the peak voltage is given as V x 2

That is Vpeak = 22

Therefore, the peak to peak value will be twice of this value.

Hence, Vpp = 42 = 5.657 Volts