Given the following hypothesis SolutionSet Up Hypothesis Nul

Solution

Set Up Hypothesis
Null, H0: U=110
Alternate,mean is different from 110 H1: U!=110
Test Statistic
Population Mean(U)=110
Sample X(Mean)=119.833
Standard Deviation(S.D)=3.971
Number (n)=6
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =119.833-110/(3.971/Sqrt(5))
to =6.065
| to | =6.065
Critical Value
The Value of |t a| with n-1 = 5 d.f is 2.015
We got |to| =6.065 & | t a | =2.015
Make Decision
Hence Value of | to | > | t a| and Here we Reject Ho
P-Value :Two Tailed ( double the one tail ) -Ha : ( P != 6.0654 ) = 0.0018
Hence Value of P0.1 > 0.0018,Here we Reject Ho

ANS:
outside the interval
to =6.065
Reject Ho
Less than 0.01