Particle 1 with a charge q1 360 mu C and a speed va 362 ms

Particle 1 with a charge q_1 = 3.60 mu C and a speed v_a = 362 m/s travels at right angles to a uniform field. The magnetic force it experience is 4.25 Times 10^-3 N. Particle 2, with a charge q_1 = 53.0 mu C and a v_2 = 1.30 Times 10^3 m/s, moves at an angle of 55.0 degree relative to the same magnetic field. Find the strength of the netic field and the magnitude of the magnetic force exerted on particle 2.

Solution

a)

Particle 1

Magnetic force

F=q₁V₁BSIn(o)

(4.25*10^-3) =(3.6*10^-6)*862*B*sin90

B=1.37 T

b)

Particle 2

Magnetic force

F=(53*10^-6)*1300*1.37*Sin55

F=0.0773 N