Hi Can anyone help me with this problem Sorry for the sidewa

Hi Can anyone help me with this problem? Sorry for the sideways picture, I wasnt able to turn it around.

9) in class we saw the notation 1, which, for any such that 0 3 ) -e. a) Find: ai) 2, aii) an aim) as aiv) av) 2, ses b) Find: bin) The 45 percentile of the standard normal distribution. bii) The 7 ercentile of the standard normal distribution. bin The 55 percentile of the standard normal distribution. biv) The 29 percentile of the standard normal distribution. c) Compare your answers to (b) and (ii) to your answers to (anand (ii); then compare your answers to bi) and (iv) to your answers to (i) and (aii). On the basis of these comparisons what can you say about how values of, are related to percentiles of the standard normal distribution? I suppose that the heights in inches) of players in the NBA are normally distributed with a mean of 78 and a variance of 25. ai) Find the 3s percentile for the heights of NBA players. aim F the 9 percentile for the heights of NBA players.

Solution

A)

Note that we can get the left tailed areas here by getting the complement of the given right tailed areas.

ai)

We get the z score from the given left tailed area. As          
          
Left tailed area = 1 - 0.45 =    0.55      
          
Then, using table or technology,          
          
z =    0.125661347   [ANSWER]

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aii)

  
We get the z score from the given left tailed area. As          
          
Left tailed area =    0.29      
          
Then, using table or technology,          
          
z =    -0.55338472   [ANSWER]

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aiii)

We get the z score from the given left tailed area. As          
          
Left tailed area =    0.95      
          
Then, using table or technology,          
          
z =    1.644853627   [ANSWER]

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aiv)

We get the z score from the given left tailed area. As          
          
Left tailed area =    0.975      
          
Then, using table or technology,          
          
z =    1.959963985   [ANSWER]

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av)

We get the z score from the given left tailed area. As          
          
Left tailed area =    0.995      
          
Then, using table or technology,          
          
z =    2.575829304   [ANSWER]  
  
  

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