Shell and Tube heat exchanger lab reportWord OUT REFERENCESM

Shell and Tube heat exchanger lab report-Word OUT REFERENCESMAILINGS REVIEW VIEW A A Aa Paragraph Table 1: The relationship between temperature and time Hot water side Fh Cold water side Time T1 T2 Fc T3 T4 (min) | (LPH) | (°C)|(\"C)| (LPH) | () | (\"C) 185 79 64.8 185 55.3 61.8 78 59.6 10 20 185 30 40 185 185 185 35 54.7 185 77.5 58.7 185 34 185 78.6 59.1185 34.2 53.6 34.3 53.8 185 34.153.4 185 58.9 185 40 185 77.8 59.1 50 185

Solution

The experiment must have been for calculating effectiveness of the heat exchanger

Effectiveness of Heat exchanger is given by

E = Q_actual / Q_{max possible ;}

Q_actual = mc(T_hi - T_ho)

Q_{max possible} = mc(T_hi - T_ci )

Therefore E = (T_hi - T_ho) / (T_hi - T_ci )

In the given experiment readings are taken for different times starting from 0min to 50min.

Total 6 readings are provided. For each reading, the effectiveness of the exchanger can be calculated and an average value of effectiveness can be calculated based on the 6 readings

Reading 1 : E₁ = (79 - 64.8)/(79 - 55.3) = 0.5991

Reading 2 : E₂ = (78 -59.6) / (78 - 35) = 0.4279

Reading 3 : E₃ = (77.5 - 58.7) / (77.5 - 34) = 0.432

Reading 4 : E₄ = (78.6 - 59.1) / (78.6 - 34.2 ) = 0.4392

Reading 5 : E₅ = (77.8 - 59.1) / (77.8 - 34.4 ) = 0.4309

Reading 6 : E₆ = (77.6 - 58.9 ) / (77.6 - 34.1 ) = 0.4299

So the average effectiveness E = ( 0.5991 + 0.4279 + 0.432 + 0.4392 + 0.4309 + 0.4299 ) / 6

E = 0.4598

Thus the average effectiveness of the heat exchanger is determined

NOTE : The first reading of your experiment seems to be wrong. You should have started taking the readings only after the system got stable. Ignoring the first reading may give you a better result.