Suppose that a survey is being planned for purposes of estim

Suppose that a survey is being planned for purposes of estimating the average number of hours spent exercising daily by adults (18 years of age or older) living in a certain community. A list of all individuals living in the town is not available; however, a list of all households is available at the office of the town clerk. For simplicity, suppose this list consists of nine households and that the information you would collect, were you to visit each household, is as shown in the accompanying table. Using the information above, identify: The population The element of the population The sampling units The frame The study (survey) variable Devise a sampling plan to estimate the average daily time expenditure on exercising by adults living in the community. Select all samples of two households from this frame, and compute the average exercising time per person for each sample. Compute the expected value of your estimate, and compare this with the actual population parameter.

Solution

a)i) All persons living in a certain community

ii) Persons who exercise

iii) List available at the office of the town clerk

iv) 9 households

v) No of adults and their hours for exercising

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b) Random sampling is better to have.

Just select any random door numbers and survey them with a sampling size reasonable large compared to total population.

From the given table, we find average for frequency distribution.

Mean =18/23 = 0.7826

Population parameter is not given hence unable to compare.

1	2	1	2
2	3	3	2
33	2	7	2
4	5	8	2
5	3	4	2
6	1	0	2
7	2	1	2
8	3	2	2
9	2	0	2
	23		18