Normal distribution mean of 0 and standard deviation 1 find

Normal distribution mean of 0 and standard deviation 1 find prob P(-1.88<z<1.88)

Solution

z1 = lower z score =    -1.88      
z2 = upper z score =     1.88      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.030054039      
P(z < z2) =    0.969945961      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.939891922   [ANSWER]