Needed in C Thank youSolutionHere is the code for you includ

Solution

Here is the code for you:

#include <stdio.h>
#include <math.h>
//Reads the inputs principal amount, rate of interest, and number of payments.
void readInputs(double *presentValue, double *rateOfInterest, int *numOfPayments)
{
printf(\"Enter the loan amount: \");
scanf(\"%lf\", presentValue);
printf(\"Enter the yearly rate of interest(as a percentage): \");
scanf(\"%lf\",rateOfInterest);
*rateOfInterest = (*rateOfInterest/100)/12;
printf(\"Enter the number of payments: \");
scanf(\"%i\", numOfPayments);
}

//Calculates the EMI per payment, given the inputs.
void EMICalc(double presentValue, double rateOfInterest, int numOfPayments, double *EMI)
{
*EMI = (rateOfInterest * presentValue) / (1 - pow((1+rateOfInterest), (-1*numOfPayments)));
*EMI = floor(*EMI*100+0.5)/100;
}
void printTable(double pV, double roI, int noP, double emi)
{
printf(\"Principal: %.2lf\ \", pV);
printf(\"Annual Interest Rate: %.2lf\ \", roI*12*100);
printf(\"Term in months: %i\ \", noP);
printf(\"Monthly Payment: $%.2lf\ \ \", emi);
printf(\"Payment\\tInterest\\tPrincipal\\tPrincipalBalance\ \");
double interest, principal;
for(int i = 0; i < noP; i++)
{
interest = pV * roI;
if(interest < 0)
interest = 0;
principal = emi - interest;
if(principal < 0)
principal = 0;
pV = pV - principal;
if(pV < 0)
pV = 0;
printf(\"%i\\t$%10.2f\\t$%10.2f\\t$%10.2f\ \", i+1, interest, principal, pV);
}
printf(\"Final Payment : $%.2lf\ \",interest+principal);
}
int main()
{
double presentValue, rateOfInterest, EMI;
int numOfPayments;
readInputs(&presentValue, &rateOfInterest, &numOfPayments);
EMICalc(presentValue, rateOfInterest, numOfPayments, &EMI);
printTable(presentValue, rateOfInterest, numOfPayments, EMI);
//cout<<\"The monthly EMI is: \"<<EMI<<endl;
//double totalInterest = EMI * numOfPayments - presentValue;
//cout<<\"Total interest paid: \"<<totalInterest<<endl;
  
}