A company manufactures and sells x radios per month The mont

A company manufactures and sells x radios per month. The monthly cost 3nd price-demand equations 3re: C(x) = 30,000 + 60x p = 600 - x / 3 0 x 1,800 Find the maximum revenue: (Points : 1) $5186,000 $5270,000 $300,S900 A company manufactures and sells x radios per month. The monthly cost and price-demand equations are: C(x) = 30,000 + 60x p = 600 - x / 3 0 x 1,800 What price should the company charge for the radios to maximize revenue? (Points : 1) $5186,000 $5270,000 $300 $900

Solution

Revenue = x(600 - x/3) To maximize diffrentiate and 0 600 - x/3 -x/3 = 0 x = 900 Revenue = 900(600-300) = 270000 p = 300