Cos2x minus sin2x minus sin 2x cos2 x sin2xcos2x sin 2x v
     Cos^2x minus sin^2x minus sin 2x = (cos^2 x - sin^2x)/cos2x + sin 2x verify the identity 
  
  Solution
cos^2x -sin^2x -sin2x = (cos^2x -sin^2x)/(cos2x + sin2x
LHS we know cos2x = cos^2x -sin^2x
So, LHS : cos^2x -sin^2x -sin2x
= cos2x -sin2x
RHS : (cos^2x -sin^2x)/cos2x + sin2x
= cos2x/cos2x +sin2x
= 1+ sin2x
Now LHS and RHS cannot be same after simplication
RHS

