If you were to take 40 sets of two random samples from a sin

If you were to take 40 sets of two random samples from a single population and compare the means of the two random samples for each set using an independent samples t-test, how many times on average would you expect the null hypothesis of no difference in means to be rejected using alpha = .05?

Solution

The null hypothesis will then be rejected 5% of the time.

Thus, 5% of 40 = 0.05*40 = 2 [ANSWER]