Solve the right triangle ABC where C 90Degree a 45 yd c 6
Solve the right triangle ABC, where C = 90Degree. a = 4.5 yd, c = 6.8 yd b = controlDEL (Round to the nearest hundredth as needed.) A = controlDELDegree (Round to the nearest tenth as needed.) B = controlDELDegree (Round to the nearest tenth as needed.)
Solution
a=4.5, c=6.8,C=90o
by law of sines a/sinA =c/sinC
4.5/sinA =6.8/sin90o
sinA=4.5/6.8
A=41.4o
A+B+C=180o
B=180o-A-C
B=180o-41.4o-90o
B=48.6o
b/sinB =c/sinC
b/sin48.6o =6.8/sin90o
b=6.8sin48.6o
b=5.10
