Find the equation of the tangent line to the curve y3xcosx a
Find the equation of the tangent line to the curve y=3xcosx at the point (pi, -3pi).
The equation of this tangent line can be written in the form y=mx+b where
m=?
and
b=?
I have m as -3 but part b was not -6pi , so I need help to find out what b is.
The equation of this tangent line can be written in the form y=mx+b where
m=?
and
b=?
I have m as -3 but part b was not -6pi , so I need help to find out what b is.
Solution
is y = 3x*cosx ?? if so the value of m = -3 and b = y - mx = -3pi + 3pi = 0