A container of car oil is supposed to contain 1000 millilite
Solution
3.
As              
               
 df = n - 1 =    9          
 alpha = (1 - confidence level)/2 =    0.025          
               
 Then the critical values for chi^2 are              
               
 chi^2(alpha/2) =    19.0227678          
 chi^2(alpha/2) =    2.7003895          
               
 Thus, as              
               
 lower bound = (n - 1) s^2 / chi^2(alpha/2) =    484.4720862          
 upper bound = (n - 1) s^2 / chi^2(1 - alpha/2) =    3412.840999          
               
 Thus, the confidence interval for the variance is              
               
 (   484.4720862   ,   3412.840999   )
               
 Also, for the standard deviation, getting the square root of the bounds,              
               
 (   22.01072662   ,   58.41952584   )
As this whole interval is greater than 20, then this confidence interval suggests that the variation in the oil containers IS NOT at an acceptable level. [CONCLUSION]
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