Homework SourseA healthcare agency does an audit of six hundred of its reco
A healthcare agency does an audit of six hundred of its records and discovers the distribution of recording errors as shown below. Use these data to calculate the mean and standivation of the errors in records.
| Errors (x) | Records |
| 0 | 353 |
| 1 | 121 |
| 2 | 69 |
| 3 | 32 |
| 4 | 16 |
| 5 | 7 |
| 6 | 2 |
| 600 |
Solution
E(X) = Mean = 466/600 = 0.7767
E(X^2) = 1188/600 = 1.98
Var(X) = 1.98-0.77672
= 1.3767
Std dev of errors = square root of variance
= 1.1733
| Errors (x) | Records f | x*freq | x^2*freq |
| 0 | 353 | 0 | 0 |
| 1 | 121 | 121 | 121 |
| 2 | 69 | 138 | 276 |
| 3 | 32 | 96 | 288 |
| 4 | 16 | 64 | 256 |
| 5 | 7 | 35 | 175 |
| 6 | 2 | 12 | 72 |
| 600 | 466 | 1188 |
