In MIPS assembly write an assembly language version of the f

In MIPS assembly, write an assembly language version of the following C code:

int A[100], B[100];

for (i=1; i < 100; i++) {

A[i] = A[i-1] + B[i];

}

Solution

The MIPS assembly sequence is as follows:

li $t0, 1 # Starting index of i

li $t5, 100 # Loop bound

loop:

lw $t1, 0($a1) # Load A[i-1]

lw $t2, 4($a2) # Load B[i]

add $t3, $t1, $t2 # A[i-1] + B[i]

sw $t3, 4($a1) # A[i] = A[i-1] + B[i]

addi $a1, 4 # Go to i+1

addi $a2, 4 # Go to i+1

addi $t0, 1 # Increment index variable

bne $t0, $t5, loop # Compare with Loop Bound

halt:

nop