Find each of the following 17 sin x 45 and 3 pi2 Solutiongi
Solution
given : sinx = -4/5 where 3pi/2 <x<2pi
cosx = 3/5 (cos is +ve in IVrth quadrant)
sin(x/2)
use the formula: sin(x/2) = sqrt(( 1-cosx)/2)
= sqrt(( 1-3/5)/2)
= sqrt( 1/5)
= 1/sqrt5

given : sinx = -4/5 where 3pi/2 <x<2pi
cosx = 3/5 (cos is +ve in IVrth quadrant)
sin(x/2)
use the formula: sin(x/2) = sqrt(( 1-cosx)/2)
= sqrt(( 1-3/5)/2)
= sqrt( 1/5)
= 1/sqrt5
