Stuck on statistics 1 Find the margin of error for the given

Stuck on statistics

1. Find the margin of error for the given values of c, s and n.   C=0.90, S=3.3, N=49   E=_

2.Find the margin of error for the given values of C,S and n. C=0.99, s=5, n=25. The margin of error is _ Round to one decimal place as needed?

3. Find the margin of error for the given values of c,s and n.   C=0.95, S=2.4, N=15?

4. In a survey of 634 males ages 18-64, 396 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population portion. Interpret the results and compare the widths of the confidence interals.

The 90% confidence interval for the population proportion p is_?

The 95% confidence interval for the population portion p is _ ?

Thanks in advance

Solution

1.

As      
      
C =    0.9  
      
Then      
      
alpha/2 = (1 - C)/2 =    0.05  
      
Thus, z(alpha/2), by table or technology, is      
      
z(alpha/2) =    1.644853627  
      
Thus, as      
      
s =    3.3  
n =    49  
      
E = z(alpha/2) * s / sqrt(n) =    0.775430996   [ANSWER]

2.

As      
      
C =    0.99  
      
Then      
      
alpha/2 = (1 - C)/2 =    0.005  
      
Thus, z(alpha/2), by table or technology, is      
      
z(alpha/2) =    2.575829304  
      
Thus, as      
      
s =    5  
n =    25  
      
E = z(alpha/2) * s / sqrt(n) =    2.575829304   [ANSWER]

3.

As      
      
C =    0.95  
      
Then      
      
alpha/2 = (1 - C)/2 =    0.025  
      
Thus, z(alpha/2), by table or technology, is      
      
z(alpha/2) =    1.959963985  
      
Thus, as      
      
s =    2.4  
n =    15  
      
E = z(alpha/2) * s / sqrt(n) =    1.214545259   [ANSWER]

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