Chapter 28 Problem 051 The figure shows a wood cylinder of m

Chapter 28, Problem 051 The figure shows a wood cylinder of mass m = 0.193 kg and length L = 0.0938 m, with N = 17.0 turns of wire wrapped around it longitudinally, so that the plane of the wire coil contains the long central axis of the cylinder. The cylinder is released on a plane inclined at an angle to the horizontal, with the plane of the coil parallel to the incline plane. If there is a vertical uniform magnetic field of magnitude 0.743 T, what is the least current through the coil that keeps the cylinder from rolling down the plane? Number Units the tolerance is +/-296 Click if you would like to Show Work for this question: Open Show Work

Solution

i = m g / (2 N L B)

= (0.193 * 9.8) / (2 * 17 * 0.0938 * 0.743)

i = 0.799 A