A random sample of n 15 men between 30 and 39 years old is
Solution
Note that              
               
 Lower Bound = X - t(alpha/2) * s / sqrt(n)              
 Upper Bound = X + t(alpha/2) * s / sqrt(n)              
               
 where              
 alpha/2 = (1 - confidence level)/2 =    0.01          
 X = sample mean =    41.8          
 t(alpha/2) = critical t for the confidence interval =    2.624494068          
 s = sample standard deviation =    12.2          
 n = sample size =    15          
 df = n - 1 =    14          
 Thus,              
               
 Lower bound =    33.53277426          
 Upper bound =    50.06722574          
               
 Thus, the confidence interval is              
               
 (   33.53277426   ,   50.06722574   ) [ANSWER, PART B]
Also,
MArgin of error = (upper-lower)/2 = 8.267225744 [ANSWER, MARGIN OF ERROR, PART A]

